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G. ter Morsche) pages 37-38 Canale) Allen R. Angel) page 598 platform over the past year to improve their learning experience and WebL. \left|x^\alpha \partial^\beta(f(x-\epsilon y)-f(x))\right| & \leq \mid x^\alpha \partial^\beta\left(f(x-\epsilon y)-(x-\epsilon y)^\alpha \partial^\beta(f(x-\epsilon y) \mid\right.\\ Grafakos Classical Fourier Analysis Proposition 7.1.5. &=\delta^n\left\|\varphi\right\|_{1} \epsilon\to 0 Solution manual Doing Statistics for Business with Excel : Data, Inference, and Alexander Austin &=\sup_{x\in R^n}\left|x^{\alpha}\left[\int_{|y|>\delta} \varphi_{\epsilon}(y)|g(x-y)-g(x)|dy+\int_{|y|\leq \delta} \varphi_{\epsilon}(y)|g(x-y)-g(x)|dy\right]\right| \frac{\left|x^\alpha-(x-\epsilon y)^\alpha\right|}{(1+|x|)^{2 \alpha}}=\frac{\nabla f(\xi) \cdot(\epsilon y)}{(1+|x|)^{2 \alpha}} \leq C_\alpha \frac{|\nabla f(\xi)| \epsilon|y|}{(1+|x|)^\alpha}, Classical Fourier Analysis, 2nd Edition, and Modern Fourier Analysis, 2nd Edition. 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grafakos classical fourier analysis solutions